1/3(4y-2)=1/2(8y+13)=

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Solution for 1/3(4y-2)=1/2(8y+13)= equation: 



1/3(4y-2)=1/2(8y+13)=

We move all terms to the left:

1/3(4y-2)-(1/2(8y+13))=0



Domain of the equation: 3(4y-2)!=0

y∈R





Domain of the equation: 2(8y+13))!=0

y∈R



We calculate fractions


(2y8/(3(4y-2)*2(8y+13)))+(-3y4/(3(4y-2)*2(8y+13)))=0



We calculate terms in parentheses: +(2y8/(3(4y-2)*2(8y+13))), so:

2y8/(3(4y-2)*2(8y+13))

We multiply all the terms by the denominator


2y8

We add all the numbers together, and all the variables

2y^8

We do not support eypression: y^8

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