1/3(4y-3)=1/9y

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Solution for 1/3(4y-3)=1/9y equation: 



1/3(4y-3)=1/9y

We move all terms to the left:

1/3(4y-3)-(1/9y)=0



Domain of the equation: 3(4y-3)!=0

y∈R





Domain of the equation: 9y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

1/3(4y-3)-(+1/9y)=0

We get rid of parentheses

1/3(4y-3)-1/9y=0

We calculate fractions


9y/(108y^2-81y)+(-3y4/(108y^2-81y)=0



We calculate terms in parentheses: +(-3y4/(108y^2-81y), so:

-3y4/(108y^2-81y

We multiply all the terms by the denominator


-3y4

We add all the numbers together, and all the variables

-3y^4

We do not support eypression: y^4

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