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t in (-oo:+oo)
(1/3)*(5-(3*t)) = (5/6)*(t-2) // - (5/6)*(t-2)
(1/3)*(5-(3*t))-((5/6)*(t-2)) = 0
(1/3)*(5-3*t)+(-5/6)*(t-2) = 0
1/3*(5-3*t)-5/6*(t-2) = 0
1/3*(5-3*t)-5/6*(t-2) = 0
10/3-11/6*t = 0
10/3-11/6*t = 0
10/3-11/6*t = 0 // - 10/3
-11/6*t = -10/3 // : -11/6
t = -10/3/(-11/6)
t = 20/11
t = 20/11
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