1/3(5y-9)=1/7(y-8)

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Solution for 1/3(5y-9)=1/7(y-8) equation: 



1/3(5y-9)=1/7(y-8)

We move all terms to the left:

1/3(5y-9)-(1/7(y-8))=0



Domain of the equation: 3(5y-9)!=0

y∈R





Domain of the equation: 7(y-8))!=0

y∈R



We calculate fractions


(7yy/(3(5y-9)*7(y-8)))+(-3y5/(3(5y-9)*7(y-8)))=0



We calculate terms in parentheses: +(7yy/(3(5y-9)*7(y-8))), so:

7yy/(3(5y-9)*7(y-8))

We multiply all the terms by the denominator


7yy

Back to the equation:

+(7yy)





We calculate terms in parentheses: +(-3y5/(3(5y-9)*7(y-8))), so:

-3y5/(3(5y-9)*7(y-8))

We multiply all the terms by the denominator


-3y5

We add all the numbers together, and all the variables

-3y^5

We do not support eypression: y^5

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