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1/3(6+r)-5=12
We move all terms to the left:
1/3(6+r)-5-(12)=0
Domain of the equation: 3(6+r)!=0We add all the numbers together, and all the variables
r∈R
1/3(r+6)-5-12=0
We add all the numbers together, and all the variables
1/3(r+6)-17=0
We multiply all the terms by the denominator
-17*3(r+6)+1=0
Wy multiply elements
-51r(r+1=0
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