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1/3(6-15x)=-2(2x+1)
We move all terms to the left:
1/3(6-15x)-(-2(2x+1))=0
Domain of the equation: 3(6-15x)!=0We add all the numbers together, and all the variables
x∈R
1/3(-15x+6)-(-2(2x+1))=0
We multiply all the terms by the denominator
-((-2(2x+1)))*3(-15x+6)+1=0
We calculate terms in parentheses: -((-2(2x+1)))*3(-15x+6), so:We add all the numbers together, and all the variables
(-2(2x+1)))*3(-15x+6
We add all the numbers together, and all the variables
-15x+(-2(2x+1)))*3(+6
Back to the equation:
-(-15x+(-2(2x+1)))*3(+6)
-(-15x+(-2(2x+1)))*36+1=0
We move all terms containing x to the left, all other terms to the right
-(-15x+(-2(2x+1)))*36=-1
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