1/3(6-15x)=3/8(40x-8)

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Solution for 1/3(6-15x)=3/8(40x-8) equation: 



1/3(6-15x)=3/8(40x-8)

We move all terms to the left:

1/3(6-15x)-(3/8(40x-8))=0



Domain of the equation: 3(6-15x)!=0

x∈R





Domain of the equation: 8(40x-8))!=0

x∈R



We add all the numbers together, and all the variables

1/3(-15x+6)-(3/8(40x-8))=0

We calculate fractions


(8x4/(3(-15x+6)*8(40x-8)))+(-9x0/(3(-15x+6)*8(40x-8)))=0



We calculate terms in parentheses: +(8x4/(3(-15x+6)*8(40x-8))), so:

8x4/(3(-15x+6)*8(40x-8))

We multiply all the terms by the denominator


8x4

We add all the numbers together, and all the variables

8x^4

We do not support expression: x^4

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