1/3(6-9x)=1/5(15x-10)

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Solution for 1/3(6-9x)=1/5(15x-10) equation: 



1/3(6-9x)=1/5(15x-10)

We move all terms to the left:

1/3(6-9x)-(1/5(15x-10))=0



Domain of the equation: 3(6-9x)!=0

x∈R





Domain of the equation: 5(15x-10))!=0

x∈R



We add all the numbers together, and all the variables

1/3(-9x+6)-(1/5(15x-10))=0

We calculate fractions


(5x1/(3(-9x+6)*5(15x-10)))+(-3x0/(3(-9x+6)*5(15x-10)))=0



We calculate terms in parentheses: +(5x1/(3(-9x+6)*5(15x-10))), so:

5x1/(3(-9x+6)*5(15x-10))

We multiply all the terms by the denominator


5x1

We add all the numbers together, and all the variables

5x

Back to the equation:

+(5x)





We calculate terms in parentheses: +(-3x0/(3(-9x+6)*5(15x-10))), so:

-3x0/(3(-9x+6)*5(15x-10))

We multiply all the terms by the denominator


-3x0

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

5x-3x=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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