1/3(6-n)=n+5

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Solution for 1/3(6-n)=n+5 equation: 



1/3(6-n)=n+5

We move all terms to the left:

1/3(6-n)-(n+5)=0



Domain of the equation: 3(6-n)!=0

n∈R



We add all the numbers together, and all the variables

1/3(-1n+6)-(n+5)=0

We get rid of parentheses

1/3(-1n+6)-n-5=0

We multiply all the terms by the denominator


-n*3(-1n+6)-5*3(-1n+6)+1=0

Wy multiply elements

-3n^2(--15n(-+1=0

We use the square of the difference formula

-3n^2(+15n(-1=0

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