1/3(6f-12)+f=1/2(4f)-2

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Solution for 1/3(6f-12)+f=1/2(4f)-2 equation: 


f in (-oo:+oo)

(1/3)*(6*f-12)+f = 4*(1/2)*f-2 // - 4*(1/2)*f-2

(1/3)*(6*f-12)+f-(4*(1/2)*f)+2 = 0

(1/3)*(6*f-12)+f-2*f+2 = 0

1/3*(6*f-12)+f-2*f+2 = 0

1/3*(6*f-12)+f-2*f+2 = 0

3*f-2*f-4+2 = 0

f-4+2 = 0

f-2 = 0

f-2 = 0

f-2 = 0 // + 2

f = 2

f = 2

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