1/3(6g+2)=12

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Solution for 1/3(6g+2)=12 equation: 



1/3(6g+2)=12

We move all terms to the left:

1/3(6g+2)-(12)=0



Domain of the equation: 3(6g+2)!=0

g∈R



We multiply all the terms by the denominator


-12*3(6g+2)+1=0

Wy multiply elements

-36g(6+1=0

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