1/3(6t+12=-3(2t-4)

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Solution for 1/3(6t+12=-3(2t-4) equation: 



1/3(6t+12=-3(2t-4)

We move all terms to the left:

1/3(6t+12-(-3(2t-4))=0



Domain of the equation: 3(6t+12-(-3(2t-4))!=0

t∈R



We multiply all the terms by the denominator


1!=0

There is no solution for this equation

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