1/3(6t-54)=t-4

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Solution for 1/3(6t-54)=t-4 equation: 



1/3(6t-54)=t-4

We move all terms to the left:

1/3(6t-54)-(t-4)=0



Domain of the equation: 3(6t-54)!=0

t∈R



We get rid of parentheses

1/3(6t-54)-t+4=0

We multiply all the terms by the denominator


-t*3(6t-54)+4*3(6t-54)+1=0

Wy multiply elements

-3t^2(6+12t(6+1=0

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