1/3(6u+3)=7-u

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Solution for 1/3(6u+3)=7-u equation: 



1/3(6u+3)=7-u

We move all terms to the left:

1/3(6u+3)-(7-u)=0



Domain of the equation: 3(6u+3)!=0

u∈R



We add all the numbers together, and all the variables

1/3(6u+3)-(-1u+7)=0

We get rid of parentheses

1/3(6u+3)+1u-7=0

We multiply all the terms by the denominator


1u*3(6u+3)-7*3(6u+3)+1=0

Wy multiply elements

3u^2(6-21u(6+1=0

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