1/3(6x+12)+2(x-7)=19

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Solution for 1/3(6x+12)+2(x-7)=19 equation: 



1/3(6x+12)+2(x-7)=19

We move all terms to the left:

1/3(6x+12)+2(x-7)-(19)=0



Domain of the equation: 3(6x+12)!=0

x∈R



We multiply parentheses

1/3(6x+12)+2x-14-19=0

We multiply all the terms by the denominator


2x*3(6x+12)-14*3(6x+12)-19*3(6x+12)+1=0

Wy multiply elements

6x^2(6-42x(6-57x(6+1=0

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