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1/3(6x+12)-3(x-7)=19
We move all terms to the left:
1/3(6x+12)-3(x-7)-(19)=0
Domain of the equation: 3(6x+12)!=0We multiply parentheses
x∈R
1/3(6x+12)-3x+21-19=0
We multiply all the terms by the denominator
-3x*3(6x+12)+21*3(6x+12)-19*3(6x+12)+1=0
Wy multiply elements
-9x^2(6+63x(6-57x(6+1=0
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