1/3(6x+12)=-7x+4+3x

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Solution for 1/3(6x+12)=-7x+4+3x equation: 



1/3(6x+12)=-7x+4+3x

We move all terms to the left:

1/3(6x+12)-(-7x+4+3x)=0



Domain of the equation: 3(6x+12)!=0

x∈R



We add all the numbers together, and all the variables

1/3(6x+12)-(-4x+4)=0

We get rid of parentheses

1/3(6x+12)+4x-4=0

We multiply all the terms by the denominator


4x*3(6x+12)-4*3(6x+12)+1=0

Wy multiply elements

12x^2(6-12x(6+1=0

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