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1/3(6x+12)=-7x+4+3x
We move all terms to the left:
1/3(6x+12)-(-7x+4+3x)=0
Domain of the equation: 3(6x+12)!=0We add all the numbers together, and all the variables
x∈R
1/3(6x+12)-(-4x+4)=0
We get rid of parentheses
1/3(6x+12)+4x-4=0
We multiply all the terms by the denominator
4x*3(6x+12)-4*3(6x+12)+1=0
Wy multiply elements
12x^2(6-12x(6+1=0
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