1/3(6x+24)-20=-1/4(12x+72)

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Solution for 1/3(6x+24)-20=-1/4(12x+72) equation: 



1/3(6x+24)-20=-1/4(12x+72)

We move all terms to the left:

1/3(6x+24)-20-(-1/4(12x+72))=0



Domain of the equation: 3(6x+24)!=0

x∈R





Domain of the equation: 4(12x+72))!=0

x∈R



We calculate fractions


(4x1/(3(6x+24)*4(12x+72)))+(-(-3x6)/(3(6x+24)*4(12x+72)))-20=0



We calculate terms in parentheses: +(4x1/(3(6x+24)*4(12x+72))), so:

4x1/(3(6x+24)*4(12x+72))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-(-3x6)/(3(6x+24)*4(12x+72))), so:

-(-3x6)/(3(6x+24)*4(12x+72))

We add all the numbers together, and all the variables

-(-3x^6)/(3(6x+24)*4(12x+72))

We multiply all the terms by the denominator


-(-3x^6)

We do not support expression: x^6

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