1/3(6x+27)2(x-3)=7

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Solution for 1/3(6x+27)2(x-3)=7 equation:



1/3(6x+27)2(x-3)=7
We move all terms to the left:
1/3(6x+27)2(x-3)-(7)=0
Domain of the equation: 3(6x+27)2(x-3)!=0
x∈R
We multiply all the terms by the denominator
-7*3(6x+27)2(x-3)+1=0
Wy multiply elements
-21x(6+1=0

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