1/3(6x+9)=3/5(2x-4)

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Solution for 1/3(6x+9)=3/5(2x-4) equation: 



1/3(6x+9)=3/5(2x-4)

We move all terms to the left:

1/3(6x+9)-(3/5(2x-4))=0



Domain of the equation: 3(6x+9)!=0

x∈R





Domain of the equation: 5(2x-4))!=0

x∈R



We calculate fractions


(5x2/(3(6x+9)*5(2x-4)))+(-9x6/(3(6x+9)*5(2x-4)))=0



We calculate terms in parentheses: +(5x2/(3(6x+9)*5(2x-4))), so:

5x2/(3(6x+9)*5(2x-4))

We multiply all the terms by the denominator


5x2

We add all the numbers together, and all the variables

5x^2

Back to the equation:

+(5x^2)





We calculate terms in parentheses: +(-9x6/(3(6x+9)*5(2x-4))), so:

-9x6/(3(6x+9)*5(2x-4))

We multiply all the terms by the denominator


-9x6

We add all the numbers together, and all the variables

-9x^6

We do not support expression: x^6

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