1/3(6x-12)+4(x-3)=5

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Solution for 1/3(6x-12)+4(x-3)=5 equation: 



1/3(6x-12)+4(x-3)=5

We move all terms to the left:

1/3(6x-12)+4(x-3)-(5)=0



Domain of the equation: 3(6x-12)!=0

x∈R



We multiply parentheses

1/3(6x-12)+4x-12-5=0

We multiply all the terms by the denominator


4x*3(6x-12)-12*3(6x-12)-5*3(6x-12)+1=0

Wy multiply elements

12x^2(6-36x(6-15x(6+1=0

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