1/3(6x-12)+4x-5=15

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Solution for 1/3(6x-12)+4x-5=15 equation: 



1/3(6x-12)+4x-5=15

We move all terms to the left:

1/3(6x-12)+4x-5-(15)=0



Domain of the equation: 3(6x-12)!=0

x∈R



We add all the numbers together, and all the variables

4x+1/3(6x-12)-20=0

We multiply all the terms by the denominator


4x*3(6x-12)-20*3(6x-12)+1=0

Wy multiply elements

12x^2(6-60x(6+1=0

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