1/3(6x-12)=4(1/2x+1)-2

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Solution for 1/3(6x-12)=4(1/2x+1)-2 equation: 


x in (-oo:+oo)

(1/3)*(6*x-12) = 4*((1/2)*x+1)-2 // - 4*((1/2)*x+1)-2

(1/3)*(6*x-12)-(4*((1/2)*x+1))+2 = 0

(1/3)*(6*x-12)-4*((1/2)*x+1)+2 = 0

1/3*(6*x-12)-4*(1/2*x+1)+2 = 0

1/3*(6*x-12)-4*(1/2*x+1)+2 = 0

2-8 = 0

-6 = 0

-6 = 0

x belongs to the empty set

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