1/3(6x-12)=41/2x+1-2

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Solution for 1/3(6x-12)=41/2x+1-2 equation: 



1/3(6x-12)=41/2x+1-2

We move all terms to the left:

1/3(6x-12)-(41/2x+1-2)=0



Domain of the equation: 3(6x-12)!=0

x∈R





Domain of the equation: 2x+1-2)!=0

We move all terms containing x to the left, all other terms to the right

2x-2)!=-1

x∈R



We add all the numbers together, and all the variables

1/3(6x-12)-(41/2x-1)=0

We get rid of parentheses

1/3(6x-12)-41/2x+1=0

We calculate fractions


2x/(36x^2-72x)+(-123x6/(36x^2-72x)+1=0

We calculate fractions

We do not support expression: x^3

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