1/3(6x-15)=-1/2(10x-4)

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Solution for 1/3(6x-15)=-1/2(10x-4) equation: 



1/3(6x-15)=-1/2(10x-4)

We move all terms to the left:

1/3(6x-15)-(-1/2(10x-4))=0



Domain of the equation: 3(6x-15)!=0

x∈R





Domain of the equation: 2(10x-4))!=0

x∈R



We calculate fractions


(2x1/(3(6x-15)*2(10x-4)))+(-(-3x6)/(3(6x-15)*2(10x-4)))=0



We calculate terms in parentheses: +(2x1/(3(6x-15)*2(10x-4))), so:

2x1/(3(6x-15)*2(10x-4))

We multiply all the terms by the denominator


2x1

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-(-3x6)/(3(6x-15)*2(10x-4))), so:

-(-3x6)/(3(6x-15)*2(10x-4))

We add all the numbers together, and all the variables

-(-3x^6)/(3(6x-15)*2(10x-4))

We multiply all the terms by the denominator


-(-3x^6)

We do not support expression: x^6

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