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1/3(6x-18)+3x=-5(-x+1)+1
We move all terms to the left:
1/3(6x-18)+3x-(-5(-x+1)+1)=0
Domain of the equation: 3(6x-18)!=0We add all the numbers together, and all the variables
x∈R
1/3(6x-18)+3x-(-5(-1x+1)+1)=0
We add all the numbers together, and all the variables
3x+1/3(6x-18)-(-5(-1x+1)+1)=0
We multiply all the terms by the denominator
3x*3(6x-18)-((-5(-1x+1)+1))*3(6x-18)+1=0
We calculate terms in parentheses: -((-5(-1x+1)+1))*3(6x-18), so:Wy multiply elements
(-5(-1x+1)+1))*3(6x-18
9x^2(6-((-5(-1x+1)+1))*3(6x-18)+1=0
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