1/3(6x-3)+5=1/2(2x+6)

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Solution for 1/3(6x-3)+5=1/2(2x+6) equation: 



1/3(6x-3)+5=1/2(2x+6)

We move all terms to the left:

1/3(6x-3)+5-(1/2(2x+6))=0



Domain of the equation: 3(6x-3)!=0

x∈R





Domain of the equation: 2(2x+6))!=0

x∈R



We calculate fractions


(2x2/(3(6x-3)*2(2x+6)))+(-3x6/(3(6x-3)*2(2x+6)))+5=0



We calculate terms in parentheses: +(2x2/(3(6x-3)*2(2x+6))), so:

2x2/(3(6x-3)*2(2x+6))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)





We calculate terms in parentheses: +(-3x6/(3(6x-3)*2(2x+6))), so:

-3x6/(3(6x-3)*2(2x+6))

We multiply all the terms by the denominator


-3x6

We add all the numbers together, and all the variables

-3x^6

We do not support expression: x^6

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