1/3(6x-5)-x=1/3-(x+1)

Solution for 1/3(6x-5)-x=1/3-(x+1) equation:

1/3(6x-5)-x=1/3-(x+1)

We move all terms to the left:

1/3(6x-5)-x-(1/3-(x+1))=0


Domain of the equation: 3(6x-5)!=0

x∈R



Domain of the equation: 3-(x+1))!=0

We move all terms containing x to the left, all other terms to the right

-(x+1))!=-3

x∈R


We add all the numbers together, and all the variables

-1x+1/3(6x-5)-(1/3-(x+1))=0

We calculate fractions


-1x+(-(x+1))+1*3)/(54x-(x+1))-45)+(-3x6/(54x-(x+1))-45)=0


We calculate terms in parentheses: +(-(x+1)), so:

-(x+1)

We get rid of parentheses

-x-1

We add all the numbers together, and all the variables

-1x-1

Back to the equation:

+(-1x-1)


We get rid of parentheses

-1x-1x+1*3)/(54x-(x+1))-45)+(-3x6/(54x-x-1-1))-45=0

We multiply all the terms by the denominator


-1x*(54x-1x*(54x+1*3)-(x+1))-3x6-x*(54x-1*(54x-1)-45)*(54x-45)+(=0

We add all the numbers together, and all the variables

-1x*(54x-1x*(54x+3)-(x+1))-3x6-x*(54x-1*(54x-1)-45)*(54x-45)+(=0

We add all the numbers together, and all the variables

-3x^6-1x*(54x-1x*(54x+3)-(x+1))-x*(54x-1*(54x-1)-45)*(54x-45)=0

We do not support expression: x^6