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1/3(6x-5)-x=1/3-(x+1)
We move all terms to the left:
1/3(6x-5)-x-(1/3-(x+1))=0
Domain of the equation: 3(6x-5)!=0
x∈R
Domain of the equation: 3-(x+1))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-(x+1))!=-3
x∈R
-1x+1/3(6x-5)-(1/3-(x+1))=0
We calculate fractions
-1x+(-(x+1))+1*3)/(54x-(x+1))-45)+(-3x6/(54x-(x+1))-45)=0
We calculate terms in parentheses: +(-(x+1)), so:We get rid of parentheses
-(x+1)
We get rid of parentheses
-x-1
We add all the numbers together, and all the variables
-1x-1
Back to the equation:
+(-1x-1)
-1x-1x+1*3)/(54x-(x+1))-45)+(-3x6/(54x-x-1-1))-45=0
We multiply all the terms by the denominator
-1x*(54x-1x*(54x+1*3)-(x+1))-3x6-x*(54x-1*(54x-1)-45)*(54x-45)+(=0
We add all the numbers together, and all the variables
-1x*(54x-1x*(54x+3)-(x+1))-3x6-x*(54x-1*(54x-1)-45)*(54x-45)+(=0
We add all the numbers together, and all the variables
-3x^6-1x*(54x-1x*(54x+3)-(x+1))-x*(54x-1*(54x-1)-45)*(54x-45)=0
We do not support expression: x^6
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