1/3(6x-5)-x=1/3-2(x+1

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Solution for 1/3(6x-5)-x=1/3-2(x+1 equation: 



1/3(6x-5)-x=1/3-2(x+1

We move all terms to the left:

1/3(6x-5)-x-(1/3-2(x+1)=0



Domain of the equation: 3(6x-5)!=0

x∈R





Domain of the equation: 3-2(x+1)!=0

We move all terms containing x to the left, all other terms to the right

-2(x+1)!=-3

x∈R



We add all the numbers together, and all the variables

-1x+1/3(6x-5)-(1/3-2(x+1)=0

We calculate fractions


-1x+(-2x+1)/(52x-47)+(-3x6/(52x-47)=0



We calculate terms in parentheses: +(-3x6/(52x-47), so:

-3x6/(52x-47

We multiply all the terms by the denominator


-3x6

We add all the numbers together, and all the variables

-3x^6

We do not support expression: x^6

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