1/3(6x-9)=6(1/3x-1/2)+5

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Solution for 1/3(6x-9)=6(1/3x-1/2)+5 equation: 


x in (-oo:+oo)

(1/3)*(6*x-9) = 6*((1/3)*x-(1/2))+5 // - 6*((1/3)*x-(1/2))+5

(1/3)*(6*x-9)-(6*((1/3)*x-(1/2)))-5 = 0

(1/3)*(6*x-9)-6*((1/3)*x-1/2)-5 = 0

1/3*(6*x-9)-6*(1/3*x-1/2)-5 = 0

1/3*(6*x-9)-6*(1/3*x-1/2)-5 = 0

-5 = 0

-5 = 0

x belongs to the empty set

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