1/3(6x-9)=6(x/3-1/2)+6

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Solution for 1/3(6x-9)=6(x/3-1/2)+6 equation: 


x in (-oo:+oo)

(1/3)*(6*x-9) = 6*(x/3-(1/2))+6 // - 6*(x/3-(1/2))+6

(1/3)*(6*x-9)-(6*(x/3-(1/2)))-6 = 0

(1/3)*(6*x-9)-6*(x/3-1/2)-6 = 0

1/3*(6*x-9)-6*(1/3*x-1/2)-6 = 0

1/3*(6*x-9)-6*(1/3*x-1/2)-6 = 0

-6 = 0

-6 = 0

x belongs to the empty set

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