1/3(6y)+12=34

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Solution for 1/3(6y)+12=34 equation: 



1/3(6y)+12=34

We move all terms to the left:

1/3(6y)+12-(34)=0



Domain of the equation: 36y!=0

y!=0/36

y!=0

y∈R



We add all the numbers together, and all the variables

1/36y-22=0

We multiply all the terms by the denominator


-22*36y+1=0

Wy multiply elements

-792y+1=0

We move all terms containing y to the left, all other terms to the right

-792y=-1

y=-1/-792

y=1/792

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