1/3(6y+12)-2(y-7)=19

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Solution for 1/3(6y+12)-2(y-7)=19 equation: 



1/3(6y+12)-2(y-7)=19

We move all terms to the left:

1/3(6y+12)-2(y-7)-(19)=0



Domain of the equation: 3(6y+12)!=0

y∈R



We multiply parentheses

1/3(6y+12)-2y+14-19=0

We multiply all the terms by the denominator


-2y*3(6y+12)+14*3(6y+12)-19*3(6y+12)+1=0

Wy multiply elements

-6y^2(6+42y(6-57y(6+1=0

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