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1/3(6y-9)=1/2(6y-8)
We move all terms to the left:
1/3(6y-9)-(1/2(6y-8))=0
Domain of the equation: 3(6y-9)!=0
y∈R
Domain of the equation: 2(6y-8))!=0We calculate fractions
y∈R
(2y6/(3(6y-9)*2(6y-8)))+(-3y6/(3(6y-9)*2(6y-8)))=0
We calculate terms in parentheses: +(2y6/(3(6y-9)*2(6y-8))), so:
2y6/(3(6y-9)*2(6y-8))
We multiply all the terms by the denominator
2y6
We add all the numbers together, and all the variables
2y^6
We do not support eypression: y^6
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