1/3(6y-9)=2y+13

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Solution for 1/3(6y-9)=2y+13 equation: 


y in (-oo:+oo)

(1/3)*(6*y-9) = 2*y+13 // - 2*y+13

(1/3)*(6*y-9)-(2*y)-13 = 0

(1/3)*(6*y-9)-2*y-13 = 0

1/3*(6*y-9)-2*y-13 = 0

1/3*(6*y-9)-2*y-13 = 0

-13-3 = 0

-16 = 0

-16 = 0

y belongs to the empty set

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