1/3(6z+24)=50

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Solution for 1/3(6z+24)=50 equation: 



1/3(6z+24)=50

We move all terms to the left:

1/3(6z+24)-(50)=0



Domain of the equation: 3(6z+24)!=0

z∈R



We multiply all the terms by the denominator


-50*3(6z+24)+1=0

Wy multiply elements

-150z(6+1=0

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