1/3(7x)=1/4(10x-2)

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Solution for 1/3(7x)=1/4(10x-2) equation: 


x in (-oo:+oo)

7*(1/3)*x = (1/4)*(10*x-2) // - (1/4)*(10*x-2)

7*(1/3)*x-((1/4)*(10*x-2)) = 0

(-1/4)*(10*x-2)+7*(1/3)*x = 0

(7*x)/3-1/4*(10*x-2) = 0

(-1/4*3*(10*x-2))/3+(7*x)/3 = 0

7*x-1/4*3*(10*x-2) = 0

3/2-1/2*x = 0

(3/2-1/2*x)/3 = 0

(3/2-1/2*x)/3 = 0 // * 3

3/2-1/2*x = 0

3/2-1/2*x = 0 // - 3/2

-1/2*x = -3/2 // : -1/2

x = -3/2/(-1/2)

x = 3

x = 3

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