1/3(7x-6)=1/6(x+6)

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Solution for 1/3(7x-6)=1/6(x+6) equation: 



1/3(7x-6)=1/6(x+6)

We move all terms to the left:

1/3(7x-6)-(1/6(x+6))=0



Domain of the equation: 3(7x-6)!=0

x∈R





Domain of the equation: 6(x+6))!=0

x∈R



We calculate fractions


(6xx/(3(7x-6)*6(x+6)))+(-3x7/(3(7x-6)*6(x+6)))=0



We calculate terms in parentheses: +(6xx/(3(7x-6)*6(x+6))), so:

6xx/(3(7x-6)*6(x+6))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)





We calculate terms in parentheses: +(-3x7/(3(7x-6)*6(x+6))), so:

-3x7/(3(7x-6)*6(x+6))

We multiply all the terms by the denominator


-3x7

We add all the numbers together, and all the variables

-3x^7

We do not support expression: x^7

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