1/3(7y-2)+1/6(4y+7)

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Solution for 1/3(7y-2)+1/6(4y+7) equation: 


y in (-oo:+oo)

(1/3)*(7*y-2)+(1/6)*(4*y+7) = 0

1/3*(7*y-2)+1/6*(4*y+7) = 0

1/3*(7*y-2)+1/6*(4*y+7) = 0

3*y+1/2 = 0

3*y+1/2 = 0

3*y+1/2 = 0 // - 1/2

3*y = -1/2 // : 3

y = -1/2/3

y = -1/6

y = -1/6

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