1/3(7z-1)=4z-3

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Solution for 1/3(7z-1)=4z-3 equation: 



1/3(7z-1)=4z-3

We move all terms to the left:

1/3(7z-1)-(4z-3)=0



Domain of the equation: 3(7z-1)!=0

z∈R



We get rid of parentheses

1/3(7z-1)-4z+3=0

We multiply all the terms by the denominator


-4z*3(7z-1)+3*3(7z-1)+1=0

Wy multiply elements

-12z^2(7+9z(7+1=0

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