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1/3(9+3)=3x+1
We move all terms to the left:
1/3(9+3)-(3x+1)=0
We add all the numbers together, and all the variables
-(3x+1)+1/312=0
We get rid of parentheses
-3x-1+1/312=0
We multiply all the terms by the denominator
-3x*312+1-1*312=0
We add all the numbers together, and all the variables
-3x*312-311=0
Wy multiply elements
-936x-311=0
We move all terms containing x to the left, all other terms to the right
-936x=311
x=311/-936
x=-311/936
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