1/3(9+6t)=1/8(16+24t)

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Solution for 1/3(9+6t)=1/8(16+24t) equation: 



1/3(9+6t)=1/8(16+24t)

We move all terms to the left:

1/3(9+6t)-(1/8(16+24t))=0



Domain of the equation: 3(9+6t)!=0

t∈R





Domain of the equation: 8(16+24t))!=0

t∈R



We add all the numbers together, and all the variables

1/3(6t+9)-(1/8(24t+16))=0

We calculate fractions


(8t2/(3(6t+9)*8(24t+16)))+(-3t6/(3(6t+9)*8(24t+16)))=0



We calculate terms in parentheses: +(8t2/(3(6t+9)*8(24t+16))), so:

8t2/(3(6t+9)*8(24t+16))

We multiply all the terms by the denominator


8t2

We add all the numbers together, and all the variables

8t^2

Back to the equation:

+(8t^2)





We calculate terms in parentheses: +(-3t6/(3(6t+9)*8(24t+16))), so:

-3t6/(3(6t+9)*8(24t+16))

We multiply all the terms by the denominator


-3t6

We add all the numbers together, and all the variables

-3t^6

We do not support etpression: t^6

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