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x in (-oo:+oo)
(1/3)*(9-(12*x)) = 0
(1/3)*(9-12*x) = 0
1/3*(9-12*x) = 0
( 1/3 )
1/3 = 0
x belongs to the empty set
( 9-12*x )
9-12*x = 0 // - 9
-12*x = -9 // : -12
x = -9/(-12)
x = 3/4
x = 3/4
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