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1/3(9-3x)=x-3
We move all terms to the left:
1/3(9-3x)-(x-3)=0
Domain of the equation: 3(9-3x)!=0We add all the numbers together, and all the variables
x∈R
1/3(-3x+9)-(x-3)=0
We get rid of parentheses
1/3(-3x+9)-x+3=0
We multiply all the terms by the denominator
-x*3(-3x+9)+3*3(-3x+9)+1=0
Wy multiply elements
-3x^2(-+9x(-+1=0
We use the square of the difference formula
-3x^2(-9x(-1=0
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