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1/3(9-6x)=x+1
We move all terms to the left:
1/3(9-6x)-(x+1)=0
Domain of the equation: 3(9-6x)!=0We add all the numbers together, and all the variables
x∈R
1/3(-6x+9)-(x+1)=0
We get rid of parentheses
1/3(-6x+9)-x-1=0
We multiply all the terms by the denominator
-x*3(-6x+9)-1*3(-6x+9)+1=0
Wy multiply elements
-3x^2(--3x(-+1=0
We use the square of the difference formula
-3x^2(+3x(-1=0
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