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1/3(90x-12)=1/2(8x+10)
We move all terms to the left:
1/3(90x-12)-(1/2(8x+10))=0
Domain of the equation: 3(90x-12)!=0
x∈R
Domain of the equation: 2(8x+10))!=0We calculate fractions
x∈R
(2x8/(3(90x-12)*2(8x+10)))+(-3x9/(3(90x-12)*2(8x+10)))=0
We calculate terms in parentheses: +(2x8/(3(90x-12)*2(8x+10))), so:
2x8/(3(90x-12)*2(8x+10))
We multiply all the terms by the denominator
2x8
We add all the numbers together, and all the variables
2x^8
We do not support expression: x^8
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