1/3(9b+1)+b-1

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Solution for 1/3(9b+1)+b-1 equation: 


b in (-oo:+oo)

(1/3)*(9*b+1)+b-1 = 0

1/3*(9*b+1)+b-1 = 0

1/3*(9*b+1)+b-1 = 0

4*b-1+1/3 = 0

4*b-2/3 = 0

4*b-2/3 = 0

4*b-2/3 = 0 // + 2/3

4*b = 2/3 // : 4

b = 2/3/4

b = 1/6

b = 1/6

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