1/3(9h*h-6h)

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Solution for 1/3(9h*h-6h) equation: 


h in (-oo:+oo)

(1/3)*(9*h*h-(6*h)) = 0

(1/3)*(9*h*h-6*h) = 0

1/3*(9*h^2-6*h) = 0

9*h^2-6*h = 0

3*h*(3*h-2) = 0

3*h-2 = 0 // + 2

3*h = 2 // : 3

h = 2/3

3*h*(h-2/3) = 0

1/3*3*h*(h-2/3) = 0

( 1/3 )

1/3 = 0

h belongs to the empty set

( 3*h )

3*h = 0 // : 3

h = 0

( h-2/3 )

h-2/3 = 0 // + 2/3

h = 2/3

h in { 0, 2/3 }

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