1/3(9j+6)=1/3j+26

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Solution for 1/3(9j+6)=1/3j+26 equation: 



1/3(9j+6)=1/3j+26

We move all terms to the left:

1/3(9j+6)-(1/3j+26)=0



Domain of the equation: 3(9j+6)!=0

j∈R





Domain of the equation: 3j+26)!=0

j∈R



We get rid of parentheses

1/3(9j+6)-1/3j-26=0

We calculate fractions


3j/(81j^2+54j)+(-3j9/(81j^2+54j)-26=0

We calculate fractions

We do not support ejpression: j^3

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