1/3(9k+12)+6=-5+7k-1

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Solution for 1/3(9k+12)+6=-5+7k-1 equation: 



1/3(9k+12)+6=-5+7k-1

We move all terms to the left:

1/3(9k+12)+6-(-5+7k-1)=0



Domain of the equation: 3(9k+12)!=0

k∈R



We add all the numbers together, and all the variables

1/3(9k+12)-(7k-6)+6=0

We get rid of parentheses

1/3(9k+12)-7k+6+6=0

We multiply all the terms by the denominator


-7k*3(9k+12)+6*3(9k+12)+6*3(9k+12)+1=0

Wy multiply elements

-21k^2(9+18k(9+18k(9+1=0

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